Махало на Капица: Difference between revisions

Revision as of 08:46, 8 June 2011

$< m a t h > | (\bar{z})^{n} | = | z |^{n}$

$\arg (z^{n}) = n \arg (z)$

$\begin{matrix} {\begin{matrix} x & = & l \sin φ \\ y & = & - l \cos φ - a \cos ν t \end{matrix} \end{matrix}$

$| \bar{z} | = | z |$

@@ Line 1: / Line 1: @@
-<m>
+<math
 |\bar{z}| = |z|
-</m>
+</math>
-<m>|(\bar{z})^n| = |z|^n </m>
+<math>|(\bar{z})^n| = |z|^n </math>
-<m> \arg(z^n) = n \arg(z) </m>
+<math> \arg(z^n) = n \arg(z) </math>
-<m>
+<math>
-\begin{matrix} \left\{ \begin{matrix} x &=& l \sin \varphi\\ y &=& - l \cos \varphi - a \cos \nu t \end{matrix} \right. \end{matrix} </m>
+\begin{matrix} \left\{ \begin{matrix} x &=& l \sin \varphi\\ y &=& - l \cos \varphi - a \cos \nu t \end{matrix} \right. \end{matrix} </math>
 <math>